EEVblog Electronics Community Forum
Products => Test Equipment => Topic started by: spiff72 on October 15, 2021, 04:41:43 pm
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Hello all,
I haven't been able to find this info through google searches (or I am not skilled enough with my google-fu to find the right search terminology)...
Simple question - if one wanted to output a sine wave of a certain amplitude, and drive current through a resistive load, what is the upper limit of current that it can source? I think the output voltage is limited to 5v (not sure offhand if this is 5Vpp or RMS), so I am curious how large of a resistor should be used to keep the current under the max allowable given my selected (not necessarily 5v) amplitude.
Thanks!
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The output of a 50 ohms AWG is in fact an ideal voltage source series with a 50 ohm resistor.
That means if your AWG is set for 1Vrms/50ohms it will deliver 1Vrms on a 50 ohms external resistor. Therefore the AWG internal source with no load is generating 2Vrms.
When you short circuit the output to measure the max I out (don't worry about shorting the output, any AWG is designed to withstand a permanent short circuit) you'll find I = 2Vrms / 50ohms, so you'll measure 40mArms with an external DMM (set the DMM to measure AC current).
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Hello,
the Arbitrary Waveform Generator has max 5 Vpp and 50 Ohm.
If your resistor has R Ohms than the max current I is
I = 5/(R+50) [App]
If R = 50 than I = 0.05 App
If R = 0 than I = 0.1 App
If your output voltage is 20mVpp <= U Vpp <= 5 Vpp than
I = U/(R+50) [App]
Best regards
egonotto
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Thanks to both of you for the responses!
I noticed that the AWG has a setting to switch between 50 ohm and High Z. Should this be set to 50 ohms for the above statements to be true?
What I would like to try is to replicate the process shown this video - evaluating a cheap current probe (which hasn't arrived yet) using the bode plot function of the Rigol:
https://www.youtube.com/watch?v=Aw-O-7UpZMQ (https://www.youtube.com/watch?v=Aw-O-7UpZMQ)
I was just trying to understand the setup...
Thanks again!
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I noticed that the AWG has a setting to switch between 50 ohm and High Z. Should this be set to 50 ohms for the above statements to be true?
Usually high Z only changes the numbers displayed on the AWG, it does not change the internal resistance of the generator. For example if you set 1V/50ohms and measure the output voltage with no load, you'll find the output has in fact 2V, not 1 as you set it. Only if you add a 50 ohms external load you'll see 1V as expected.
That is why the high Z setting. When you set 1V/High Z you'll measure 1V output with no load (and only 0.5V output if you attach a 50 ohms load).
I didn't watch the video you linked.
The circuit inside a generator has a series 50 ohms at all times, HighZ or not, like explained in this video:
https://www.youtube.com/watch?v=e446nQ9cXdc (https://www.youtube.com/watch?v=e446nQ9cXdc)
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Thank you! That video helped immensely (showing me the voltage divider circuit). It has now clicked for me!