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Ok to use BNC breakout wire as oscilloscope input for aux trigger
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Ian.M:
Unlikely. More probable the cheap BNC lead's plug doesn't meet specs.
Infraviolet:
If I measure the cheap BNC connecotor with calipers from the "bottom" of the bayonet dip to the "face" of the locking ring I get:

4.8mm
(see attachment for dimension image)

I can't make this measurement on my existing probes as they are plastic shielded around the BNC connector, so can anyone please check some BNC connectors they have to hand and see how this length turns out for them. The I'll know if the cheaplead has too long a length here.

Thanks
Ian.M:
I don't think the measurement you took is necessarily meaningful, as the base of the locking ring doesn't contact any surface of the jack in normal use so its height relative to the contacts may vary.  The position of the end holes of the spiral locking grooves relative to the contacts is what matters.

Amphenol have mechanical specs for the BNC connector.  See https://www.amphenolrf.com/connectors/bnc-connectors.html
The Jack drawing at the bottom of the page has the key dimensions you need, giving the distance the locking pins are from the lip of the shell, and the min. clearance between them and the panel. (in fractional inches).

Note that Russian clones of BNCs have slightly different dimensions due to (deliberate) rounding of US customary measurements when converting to metric, so don't mate easily with BNCs.

Try mating the offending BNC a few time with a sacrificial BNC jack, and forcing the ring round.  The locking ring spring may well collapse a bit allowing it to fit.
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