thanks so much, johansen and Aurora for your help
These units are not designed to be dismantled so modification would seem unlikely. I do have one in the lab but have no access to it tonight. In your position, I would test the probe on a known DC voltage from a power supply. Your meter will provide you with a reading that you can confirm accurate or not. 10V should give you a reading of 0.01V on your meter ;-). You could also use it to measure your city ac electricity supply and compare the reading with that provided by your meter direct.
you're absolutely right, Aurora, I can make some tests directly measuring low voltages and seeing their accuracy, I will do some tests tomorrow ...

is easily removable, but I do not think that is modified. the voltage divider (or 'shunt') apparently is not touched, and is a printed circuit board, apparently ceramic, with printed resistors, so it appears to be original from Fluke
Do not trust schematics provided by the OEM unless you can confirm the revision of your equipment/probe is the same as that shown in the the schematic. Manufacturers reserve the right to change products.
in the manual says this:
"The 80K-6 represents a load of approximately 75 megohms to the
circuit being measured (13 mA per 1 kV). See Figure 1. To more
accurately determine the load resistance, measure the resistance
of the 80K-6 at its voltmeter connector and multiply the measured
value by 1000"
maybe I've misunderstood, or there is also the possibility that fluke has changed the values ??of the voltage divider, as Aurora says ...
but the most important thing is that I can prove it easily by measuring DC voltages like 180V and 230VAC that I have available and I had not thought of. measuring voltages of this magnitude I can test it with complete accuracy.
many thanks!
good day, mates!