From the spec, you just need the external oscillator to go from below the logic 0 level (but not below the operating level) to above the logic 1 level (but not above VDD).
It is much easier to answer your questions if you state what this "functional generator" is, and what its properties are.
Specifically, you don't want to use a sine wave symmetrical around ground into the CMOS binary input. If that's what you have, then capacitor couple it to a DC voltage divider to establish the proper center voltage level. With CMOS inputs, you don't need to use small resistances, and the capacitor should be much larger than the input capacitance and large enough to pass your frequency into the resistors.
Earlier, when I asked you for the external source, you posted data for a CMOS oscillator that runs on 1.2 V. Its output would be just enough peak-to-peak voltage to drive the load you posted (3.3 V CMOS part), but the DC levels are not quite right. Since your original post said 3.3 V signal, I assumed you had a 3.3 V CMOS oscillator part.
If you mean a function generator that can drive a 50 ohm load, the appropriate voltage divider would probably load down a CMOS source, and might even damage it. However, if the function generator square-wave output can be adjusted, keeping the lower voltage set to zero, you can verify (carefully) how much voltage is required to clock the load.
Please specify exactly what you are connecting: the "voltage divider" you asked for, as a black box, will affect the driver and the load will affect the voltage divider. One cannot choose the interface without knowing what is being interfaced.