I suspect a dead optocoupler which is supposed to switch on the power supply and diode voltage is 1v. however the Vce is ~10v
The diode is an infrared LED, which has a far higher forward voltage, than an ordinary silicon diode, normally around double. If you're only putting 1V across the diode, then hardly any current will flow, so the transistor will be off.
As mentioned above, pass about 10mA through the diode and the transistor should measure closed circuit.