Author Topic: Why do i get better battery life than my calculation?  (Read 4876 times)

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Online Siwastaja

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Re: Why do i get better battery life than my calculation?
« Reply #25 on: December 16, 2021, 01:58:36 pm »
Battery voltage on Lithium batteries is not a reliable measure. What load are you applying whilst trying to infer SoC?

Maybe, but OP does not use lithium battery but a lithium ion battery, where voltage is a good enough SoC indicator. If they measure 4.1V, that means SoC is at least 90%. If they measure 4.1V under load, that just means it's even closer to 100%.

For low-power devices, voltage is very reliable indicator. You can always filter out high-current peaks if you so wish.
 

Offline ElectricPowerTopic starter

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Re: Why do i get better battery life than my calculation?
« Reply #26 on: December 19, 2021, 07:18:10 am »
19 days and still going. Battery voltage is now 3.85V

« Last Edit: December 19, 2021, 11:36:28 am by ElectricPower »
 

Offline cemelec

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Re: Why do i get better battery life than my calculation?
« Reply #27 on: December 19, 2021, 09:04:26 am »
Battery capacity is rated at a given discharge rate,  e.g. a 10Ah cell may be rated as 1A for 10 hours.

That same cell will not give 2A for 5 hours, or 10A for 1 hour. Indeed at 10A discharge you might only get 5-6 Ah.

The converse is true, at a very low discharge rate (as in your case) you will get significantly more than the rated capacity, as evidenced by your experience.
 

Online Siwastaja

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Re: Why do i get better battery life than my calculation?
« Reply #28 on: December 19, 2021, 11:16:10 am »
Battery capacity is rated at a given discharge rate,  e.g. a 10Ah cell may be rated as 1A for 10 hours.

That same cell will not give 2A for 5 hours, or 10A for 1 hour. Indeed at 10A discharge you might only get 5-6 Ah.

The converse is true, at a very low discharge rate (as in your case) you will get significantly more than the rated capacity, as evidenced by your experience.

Complete BS. Does not apply to li-ion cells. You are describing the Peukert law that models the behavior of lead acid cells. No one uses lead-acid cells on IoT gadgets. This was already discussed, so it would be nice if you read the thread before wasting our time, thank you in advance.
« Last Edit: December 19, 2021, 11:20:03 am by Siwastaja »
 

Offline cemelec

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Re: Why do i get better battery life than my calculation?
« Reply #29 on: December 19, 2021, 05:16:18 pm »
Dear Siwataja

My apologies, I didn't realise you owned this thread, or indeed this forum, otherwise I would have shown more servility.

You're still wrong mind.
 

Offline Nusa

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Re: Why do i get better battery life than my calculation?
« Reply #30 on: December 19, 2021, 05:39:16 pm »
Battery capacity is rated at a given discharge rate,  e.g. a 10Ah cell may be rated as 1A for 10 hours.

That same cell will not give 2A for 5 hours, or 10A for 1 hour. Indeed at 10A discharge you might only get 5-6 Ah.

The converse is true, at a very low discharge rate (as in your case) you will get significantly more than the rated capacity, as evidenced by your experience.

Complete BS. Does not apply to li-ion cells. You are describing the Peukert law that models the behavior of lead acid cells. No one uses lead-acid cells on IoT gadgets. This was already discussed, so it would be nice if you read the thread before wasting our time, thank you in advance.

As usual, the truth is somewhere in the middle: https://iopscience.iop.org/article/10.1149/1945-7111/abad69
 

Offline bdunham7

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Re: Why do i get better battery life than my calculation?
« Reply #31 on: December 19, 2021, 06:12:54 pm »
As usual, the truth is somewhere in the middle: https://iopscience.iop.org/article/10.1149/1945-7111/abad69

That paper contradicts every model, both theoretical and demonstrated, of Li-Ion battery operation that I know of.  I didn't scour every detail, but it seems to me that the differences in capacity that they are trying to fit to a Peukert-like equation are simply attributable to the remaining charge left in the cell when it reaches some arbitrary cutoff voltage at some rate of discharge.  Peukert's Law and the Peukert effect are a description of an identifiable effect that occurs in electrochemical batteries using a redox reaction like the common lead/acid/lead oxide variety.  Li-Ion batteries work on a much different principle and can't really tolerate 'slip', or mismatch in the charge-discharge amounts measured in coulombs.  For much the same reason they cannot tolerate float charges.

Here's a telling excerpt from the paper:

In conclusion, we note one important fact. For any batteries, a high enough current always exists, at which already at the battery discharge start, on its terminals, the voltage will be lower of the lower cutoff value, i.e. for such high current, the battery released capacity will be equal to zero. However at the present time, this fact is taken into consideration by neither the classical Peukert's equation nor any of its generalizations.

With a lead-acid battery you can directly and fairly definitively measure it's charge with a hydrometer, or by other means.  With an Li-Ion battery you do that by letting its temperature stabilize and them measure the OCV and cell temp.  I can pretty much guarantee you that all of the cells that they tested with different charge rates had different charges remaining when measured this way, and thus more current could have been recovered at a lower rate--IOW the cell wasn't really discharged.  And that could be proven by taking two cells subject to the two different rates and then comparing them--they won't be in the same state.  You do get a bit of a similar effect with lead-acid batteries, but with those, you can have two cells arrive at the same absolute state of discharge, measured in the same way, after providing different amounts of ampere-hours at different rates.  AFAIK, that won't happen to any degree of significance with Li-Ion cells unless you damage them.

That whole paper looks like a PhD-level attempt to hammer a square peg into a round hole.  I'd like to see what Jeff Dahn would say about it.  Perhaps I'm wrong.
« Last Edit: December 19, 2021, 07:33:07 pm by bdunham7 »
A 3.5 digit 4.5 digit 5 digit 5.5 digit 6.5 digit 7.5 digit DMM is good enough for most people.
 
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Offline wizard69

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Re: Why do i get better battery life than my calculation?
« Reply #32 on: December 19, 2021, 08:00:40 pm »
I see.

So all my calculation regards to battery life do not give me any good data at all. That was new for me. Measured voltage to day (17 days in use) and the voltage shows 3.98V.

You should be careful here because many Lithium chemistries have  very flat voltage curve while discharging.   You will want to know what the specific voltage is to consider a battery fully discharged.   Beyond that temperature itself is a factor.  Also it is not impossible for a battery to be better than speced out of the box.   Also there is a drop off in performance after a few charge/discharge cycles before the battery starts to age at a more linear rate.    I really wouldn't assume that the battery will be doing this well after some usage.

edit:

I'm likely bumping heads with people that know a lot more than I do about batteries but on the other hand it is pretty clear that not all chemistries are the same.    In fact with everybody and their brother going after the EV market, batteries are becoming "interesting" to say the least.   If you want to know what is going on with a battery it is a good idea to have the data sheet and manufactures application notes, for a specific model.
« Last Edit: December 19, 2021, 08:14:50 pm by wizard69 »
 

Online Siwastaja

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Re: Why do i get better battery life than my calculation?
« Reply #33 on: December 19, 2021, 08:06:27 pm »
As usual, the truth is somewhere in the middle: https://iopscience.iop.org/article/10.1149/1945-7111/abad69

No, the truth is "not in the middle", the truth is the truth, you know, the actual physical reality. Truth does not follow social games, we don't "make deals" in order to be nice to each other. Giving correct information is my only priority, everything that works against it, I ignore or fight against.

Yes, it's very common mistake to mis-apply the Peukert formula due to small observable capacity difference caused by the combination of Low-Voltage Cutoff (which is always arbitrary, you have to use something) and equivalent DC resistance of the cell. In any case, the effect on capacity is small, a few %. The question is only about whether the exponential Peukert law is a good model for li-ion, and the answer is no.

If you choose LVC poorly, or the application demands high currents and can't work down to lower voltages (which is of poor design, similar to crappy gadgets which refuse to work with alkaline cells at 1.2V, causing unused charge to remain), then yes, you can force-fit the observations into the Peukert law and calculate a non-unity Peukert exponent. This does not make the Peukert law a suitable tool for analyzing li-ion cells, which is why it is never normally used. Fitting an exponential formula into a fairly linear system makes little sense.

Nothing prevents you from:
* Using low enough LVC, or
* Using dynamic LVC, or
* CC-CV discharging the cell

to fully utilize the charge in the li-ion cell. Done that way, calculated Peukert exponent will be very very close to 1.

Finally, li-ion cells are rated by the manufacturer typically at 0.5C or 0.2C discharge down to typically 2.5V or 2.8V. There is very very little extra to be gained, no matter how low current you are using. Maybe a few %, unless you take a risk of overdischarging the cell.

Yes, some of us actually have a scientist background, some of us have published papers in peer reviewed journals, or reviewed papers by others so know the process, and some of us have actually made some career on analyzing and testing li-ion cells. I'm really not the only one here who qualifies on all these. Those who have an ego issue and need to try to shine on something they have not the slightest clue about, maybe think about what damage it causes to the forum and the projects of others? The options for us really are stay quiet and let the wrong information shine, or correct the errors with the risk of the clueless egoists starting to fight back, derailing the thread. What would you choose if I spewed some BS about something you know very well, and you think is important? Think about this for a while and forget about your pride, it's worthless, mine at least is and I love to be shown wrong. Thank you in advance.
 
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Online Siwastaja

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Re: Why do i get better battery life than my calculation?
« Reply #34 on: December 19, 2021, 08:08:00 pm »
You should be careful here because many Lithium chemistries have  very flat voltage curve while discharging.

You can guess from the 4.2V voltage mentioned that this is a typical consumer-type LCO, NCA or NMC cell. Their curves are not that flat, voltage gives fairly good estimate of SoC. If it reads 4.1V, it has to be around 90%, it just simply can't be something like 70% for example.
 

Offline wizard69

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Re: Why do i get better battery life than my calculation?
« Reply #35 on: December 19, 2021, 08:24:13 pm »
You should be careful here because many Lithium chemistries have  very flat voltage curve while discharging.

You can guess from the 4.2V voltage mentioned that this is a typical consumer-type LCO, NCA or NMC cell. Their curves are not that flat, voltage gives fairly good estimate of SoC. If it reads 4.1V, it has to be around 90%, it just simply can't be something like 70% for example.

Well it is flat compared to most alternative batteries.   My concern is that we really would be better off knowing specifically what that battery is.   That is its manufacture, type and other information.    The reality is this is a rapidly changing field with fairly constant tweaking to chemistries.   It seems like almost yearly that we have higher energy batteries in the same form factor.
 

Offline bdunham7

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Re: Why do i get better battery life than my calculation?
« Reply #36 on: December 19, 2021, 08:24:20 pm »
Yes, some of us actually have a scientist background, some of us have published papers in peer reviewed journals, or reviewed papers by others so know the process

The paper he cited was published in the Journal of the Electrochemical Society (which I know nothing about) and the primary author is a professor at Don State Polytechnic, Rostov-on-Don, Russia.  So I could certainly see how someone might find it credible and I'm still wondering if perhaps I missed the point as opposed to them being wrong.  I didn't comb through it for details because I think they are obscuring their experimental data a bit, or at least I couldn't find it easily.  I'm inferring that they used the manufacturer's listed LCV in each case and I don't see any of the very careful measurement of total charge and discharge currents and energy as I have in other studies. 

https://orcid.org/0000-0002-1613-8659
« Last Edit: December 19, 2021, 08:37:48 pm by bdunham7 »
A 3.5 digit 4.5 digit 5 digit 5.5 digit 6.5 digit 7.5 digit DMM is good enough for most people.
 

Offline bdunham7

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Re: Why do i get better battery life than my calculation?
« Reply #37 on: December 19, 2021, 08:36:32 pm »
Their curves are not that flat, voltage gives fairly good estimate of SoC.

Certainly not flat like a Lithium-Iron or Thionyl primary cell, but to be fair, a lot of Li-ion cells (especially NMC in my limited experience) have a fairly wide area in the middle of the discharge curve where you need to know the temperature of the cell quite accurately to determine the SOC from the OCV.  My car's BMS uses quite a few tricks to accurately indicate charge in this area, it certainly doesn't rely on voltage alone.   At the ends, no doubt-->4.1 is pretty full and <3.5 is pretty dead.
A 3.5 digit 4.5 digit 5 digit 5.5 digit 6.5 digit 7.5 digit DMM is good enough for most people.
 

Online Siwastaja

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Re: Why do i get better battery life than my calculation?
« Reply #38 on: December 20, 2021, 08:49:28 am »
Well it is flat compared to most alternative batteries.

Lead acid, NiCD, NiMH are all flatter. LFP is also flatter. So are lithium primary cells.

Alkaline primary cells are pretty much the only battery tech that comes in my mind which is less flat (or quite similar) to consumer gadget LCO/NCA li-ion.

Yes, some NMCs are flatter in the middle than classic consumer LCOs, making it hard to make distinction between say 45% and 55% SoC. But rarely a typical IoT device needs this level of accuracy. Even laptop computers with sophisticated Coulomb counters (which finally kind of work) tend to sacrifice the 1% resolution and show some 3- or 4-level bar graph in the UI, because people are fine with this.

In general, I suggest people actually measure the curves, or look them up because someone else has done that already. lygte-info.dk has tested a lot of li-ion cells.

For example, look at the classic Samsung INR18650-29E (thousands and thousands have gone through my hands into battery systems):
https://lygte-info.dk/review/batteries2012/Samsung%20INR18650-29E%202900mAh%20%28Blue%29%20UK.html

As you can see, first the capacity seems to drop a bit as a function of discharge current, but then as you expect a total collapse per the exponential Peukert Law, the opposite happens, the cells seem to gain more capacity at highest discharge currents! How is that possible?

It's possible because the apparent loss of capacity is actually about the increasing voltage drop dV = dI * R_esr with increasing I; this causes the test to be terminated early, as the cell hits the arbitrary 2.8V stop condition (datasheet condition is given as 2.5V, mind). In highest current test, however, the cell heats up considerably because of I^2*R losses (where the square I^2 term swamps the linear dV = dI*R). High temperature then lowers the heavily temperature-dependent R_esr of the cell, so the voltage drop is actually lower at the highest discharge currents, allowing the test to run for longer.

All of this can be avoided by using dynamic (current-dependent) low-voltage cutoff point. Or, just accepting small (in this lygte-info test, 7%) differences in capacity as a function of discharge current.
« Last Edit: December 20, 2021, 08:53:02 am by Siwastaja »
 
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Online RoGeorge

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Re: Why do i get better battery life than my calculation?
« Reply #39 on: December 20, 2021, 01:40:50 pm »
https://lygte-info.dk/review/batteries2012/Samsung%20INR18650-29E%202900mAh%20%28Blue%29%20UK.html

Very useful measurements and charts, thank you.  :-+

I'm trying to sort out my pile of recheargeables collected with time.  Apart from a few LiIon, most of them are 1.2V NiMH AA/AAA, a few NiCd, and a few battery packs from the handheld tools I have (either LiIon or NiCd).  In total probably less than 50-100 batteries, but still too many to measure them one by one.  I'm building a multichannel voltage datalogger as we speak, so to discharge them in batches of 10-20 or so, and any good data would help with the design ant the software.

Do you happen to have any link with similar measurements/info, but for 1.2V NiMH and/or NiCd cells, please?

Offline tunk

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« Last Edit: December 20, 2021, 03:36:44 pm by tunk »
 
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Offline ElectricPowerTopic starter

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Re: Why do i get better battery life than my calculation?
« Reply #41 on: December 23, 2021, 01:28:01 am »
23 days:

 

Offline ElectricPowerTopic starter

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Re: Why do i get better battery life than my calculation?
« Reply #42 on: December 26, 2021, 08:57:15 am »
26 days has gone, and the battery is now dead. 2.72V and the TP4056 has shut the battery off.

26 days is still impressive, but yes, from 3.7 ish volt and down it falled wery quick. From 3.7V to 2.72 in 2 days.
 

Offline bdunham7

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Re: Why do i get better battery life than my calculation?
« Reply #43 on: December 26, 2021, 02:59:48 pm »
26 days has gone, and the battery is now dead. 2.72V and the TP4056 has shut the battery off.

26 days is still impressive, but yes, from 3.7 ish volt and down it falled wery quick. From 3.7V to 2.72 in 2 days.

What is the ambient temperature in your lab?
A 3.5 digit 4.5 digit 5 digit 5.5 digit 6.5 digit 7.5 digit DMM is good enough for most people.
 

Offline ElectricPowerTopic starter

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Re: Why do i get better battery life than my calculation?
« Reply #44 on: December 26, 2021, 05:27:17 pm »
26 days has gone, and the battery is now dead. 2.72V and the TP4056 has shut the battery off.

26 days is still impressive, but yes, from 3.7 ish volt and down it falled wery quick. From 3.7V to 2.72 in 2 days.

What is the ambient temperature in your lab?
About 15 degrees celcius.
 

Offline bdunham7

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Re: Why do i get better battery life than my calculation?
« Reply #45 on: December 26, 2021, 11:38:40 pm »
About 15 degrees celcius.

That's interesting, I would expect the 'edge of the cliff' to be a bit under 3.6V at very small draws unless you have an unusual cell chemistry, like the ones marketed as 3.8 or 3.85 nominal voltage.  But I've only seen those in pouch cells.  But as you've noticed, wherever the 'cliff' is, you don't recover much additional energy going over it.
A 3.5 digit 4.5 digit 5 digit 5.5 digit 6.5 digit 7.5 digit DMM is good enough for most people.
 

Offline mayor

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Re: Why do i get better battery life than my calculation?
« Reply #46 on: December 27, 2021, 12:33:16 pm »
Hi OP,

this might be an interesting read (shameless plug!):

https://hackaday.io/project/182323-long-range-thermocouple-temp-sensor
 

Online Siwastaja

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Re: Why do i get better battery life than my calculation?
« Reply #47 on: December 27, 2021, 01:39:18 pm »
Yeah, I'm a bit surprised it fell off so quickly below 3.60V - 3.60V is usually around 40% SoC -, but that said, curves can be quite different between products.

Is it reading 2.72V even with load disconnected, or just during peaks?
 

Offline ElectricPowerTopic starter

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Re: Why do i get better battery life than my calculation?
« Reply #48 on: January 30, 2022, 10:03:52 pm »
I tried with an another 18650, and i get 29 days lifetime. It was an 2.500mA noname battery from an bran new but sheap power bank.
 


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