I’m very new to circuit modeling, and I’m trying to design a circuit in a Spice-powered designer. I want to insert a black-box model of an ideal 12A@5v load.

I know a “current source” is a “truly ideal” model, but (presumably because voltage would equal infinity) the simulator throws an error when the current source does not have something attached to both ends. I want to be able to “switch off” my load, so this doesn’t work.

Is the solution simply using Ohm’s law to calculate a resistor value and then use a resistor as my load? 5/12=0.41666… so would a 0.4166? resistor suffice to simulate a back box that draws 12A at 5v?

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