I have a couple Inverters that a power surge or lightning took out during a storm. The control-driver boards are what I'm having issues with repairing. The H bridge is not a problem. No schematics available making it more difficult. Luckily, I've purchased a new control board to compare resistance and voltage readings. I'd love to be able to repair the damaged boards for future backups. New ones are not cheap!
They are a 24v, 6kw, 240v split phase and a 24v, 4kw, 120v. Both of the control boards are basically identical. There is no noticeable physical damage on either.
The main issue-question I'm having is with the supplies for the op amps. The 24v comes into the board through a diode and then appears to go to a small pcb mount transformer. Kinda odd that the op amps are supplied with +12.6v and -9.5v. There is a 5v supply that only powers the 14011B Nand. The 7805 is supplied with the 12.6v rail.
The +12.6v appears on the ER806 diode. The -9.5v appears on the UF204 diode. Shown in the one photo. The +12.6v supplies the 7805 regulator.
I initially thought that the positive and negative rails were created by the tranformer controlled by the 3843B PWM controller and the IRF640N mosfet. The output on the 3843B does go to the gate of the mosfet. It's powered though by the 12.6v rail which would not be there on power up.
My my question right now is understanding how the positive and negative rails are created.
Anyone out there could explain this?
Also, why would they do it this way with an uneven positive and negative rail?
Thanks, Ken