hello,
in designing i was following the below two guides:
https://www.nxp.com/docs/en/application-note/AN10441.pdfand
http://www.ti.com/lit/an/slva689/slva689.pdfi've RTC chip that uses i2c, 5v, and mcu 3v3
why level shifting?:
note [6]: The I2C-bus is 5 V tolerant.
and you can see VIH = 0.7 * Vdd = 0.7*5 = 3.5V.
you can see my design here from Tr [1000nS] was for standard mode 100khz:
and you can see that its not good at fast mode 400khz.
although, the method for shifting in
AN10441 is applicable for fast mode i2c. but, if i do the calculations (assuming voltage drop at Q1 and Q2 is 0V):
Rp (min) @ 5v = 5v - 0.4v /
3mA = 0.92K ohm
Rp (max) @ 5v or 3v3 = 300nS / 0.8743 * Cb[400pF] = 0.86K ohm
Rp (min) @ 3v3 = 3.3 - 0.4 /
3mA = 0.96K ohm
you can see that maximum resistor is less than minimum....
of course you the key is in IOL but i cant imagine that i put IOL more than 2mA !!!!
or is it
?!!!
there is also me imagining that 3ma is devided into the two resistors (Rpull up) at 5v and 3v3 so i should assume it ~ 1.5ma ?! that makes it worse.
so my question how do i calculate the right values of pull up resistors?
and by the way, 400pF (bus capacitance) is the worst case? (the more devices or longer traces/wires the more capacitance?) so it could be less than 400pF?