the inductance SHOULD be around 300uH for the 6v coil and 120 uH for the 12v one. i measured it using a somewhat inaccurate tool that i build quite some years ago, but i measured the coil with my tool and i matched the value on the display by using a set of axial inductor of known value that i had lying around. far from perfect but it should at least get us close.
i attached an image of the flywheel. its not exacly like mine but very close.
Hm, is that magnets on the inside, and the coils face into there?
I guess it's metal all the way around, so that answers that, too.
The relevance being, if the coil is magnetically open, then its inductance will be higher between magnets; whereas, facing a lump of metal regardless of position, the metal reflects magnetic fields and inductance will be lower.
So it also matters if you measured the inductance in situ or not. But also, if you measured in free air, we can take that as a worst-case figure.
The other thing is, the coil is likely constructed on laminated iron, which is quite lossy above some 100s of Hz. Depending on what frequency you measured at, you may find less inductance than is really there*, and more resistance (low Q factor). It may also depend on signal level. Your average dollar store inductance tester doesn't tell you about all this, so yeh, could be whatever; but it's in the right ballpark at least, good enough to work off of.
*Compared to, whatever frequency the highest inductance is measured at. Probably a low frequency, but not so low that wire DCR dominates. There's a sweet spot between frequency extremes. Which makes sense: no inductor is suitable for all frequencies, you have to use the stored magnetic energy before it bleeds away in DCR, but also not at such a fast rate that it's largely lost in the laminations and stuff.
i tried running some math here (feel free to correct me, im doing a lot of guesstimating) and assuming that only he 12v coil is working (ie the other one is doing negligible stuff), it should be able to pump out around 3A of peak current (its the short circuit current), assuming a inductance of 120uH it means that its storing 0.5*3^2*120*10^-6 J of energy, which is about 0.5mJ. assuming im dumping all that energy in a RC snubber, with a 1uF capacitor charged at 14V i have 0.1mJ of energy, i end up with 0.6mJ stored in the capacitor, which means that it gets charged at a voltage of around 35V, which sound feasible.
Nah, you're already there in the first part -- don't worry about the cap energy, it just follows along. We want all the excess (magnetic) energy into the resistor, eventually; the L and C will ring down somewhat in the process, maybe taking some time to do it, but that only depends on the L/R time constant, and the energy balance is true for any R > 0. For a single event, assuming it's not interrupted with overlapping events of course. We merely want C large enough that little ringing, and a low enough peak voltage, occurs during this.
The C will take a little extra energy due to the voltage swing from the generated voltage, too, so we want to keep its value small.
Anyway, if we say we're doing 1000 such events per second, even if always at full peak current (somewhat more than 3A, probably?), that's power equals just so many times the energy -- or a half watt, or a few times more at peak current.
So it shouldn't be a big deal!
If we want a peak voltage (in excess of the generated voltage) of say 30V, at max peak current (say 6A), and it's the worst case figure 300uH, and say we switch at 100Hz (but always magically on the generated peaks), then we need to dissipate 0.5 (6A)^2 (300uH) (100Hz) = 0.54W, and the resistor will be (30V) / (6A) = 5 ohms. 4.7 is a common value, and maybe make it a metal-oxide 2W power resistor just in case.
To avoid ringing, we need C > L/R^2, or 13.6uF. Pretty large, really; the resonant frequency is 2.5kHz. We might tolerate a higher peak voltage, or use a TVS clamp instead (rated to avoid conduction at max RPM -- need peak voltage when you can get around to this). We can also put this RC damping after the FWB, so it's not exposed to raw AC (which would dissipate a lot of power), and any excess charge just gets dumped into the load/bulk cap/battery the next time it turns on again.
And obviously, MOSFET needs to be rated for at least as much peak voltage as the TVS.
For best EMI, I wonder if maybe, like, 100nF + 22R (in series), from GND to each winding, and then a bigger one (but not the full 13uF, maybe just 1-4.7uF to help "take the edge off"?) and a TVS, on the rectified side. Reason for the winding side is, the diodes themselves have some switching noise, so this just helps things stay a little quieter.
Speaking of EMI, maybe a "hash choke" on the output terminal could be helpful, guessing... well wait a minute, what is ignition on this thing anyway, if magneto it's probably not anything huh? (Just keep wires away from the ignition cable itself!) And I suppose if battery can be optional, you definitely won't have electronic ignition (even points!), heh...
...So yeah, that should cover for any source of interference you might need to worry about around this circuit. I would suggest building it on perf board, mounted to the lid, using mounting screws for grounding. If the lid seals to the box with a gasket, you may want a ground lug between them as well, just in case. And the box or lid can be mounted in turn to the chassis, which will be common ground as usual, I'm guessing? Keep the connections (especially EMI components) close to a ground connection; so, the R+Cs and the output bulk cap, basically.
If you want to get fancy, you can even mount the transistor, and resistor (get a TO-220 style one instead), to the enclosure -- another good reason to choose the lid, they can mount there while also soldering directly into the circuit board, without hassling with fly leads or awkward hardware.
(Note that you'll want to drill access holes through the board, to reach the hardware underneath!)
assuming on the output caps a load current of 1.5A, assuming that the coil is able to put out around 2Arms of current, assuming ~14mF of output capacitance (the same that i currently have) and assuming that i can tolerate a 0.5Vpp of output ripple, i get 14ms during the charge cycle and around 4.6ms during the discharge cycle. this means that i switch the mosfet off at around 55hz, which means that i should dissipate around 55hz*0.5mJ = 27mJ/s =27mW of continuos power in the damping resistor. plus the apparent current that flow in said resistor.
does any of this make any sense?
Careful -- RMS is not DC average! Especially with a peaky waveform like that, it will be even higher (than the DC output).
Typical case for AC mains is input Irms being a bit over double the Idc. (This is somewhat balanced by Vout also being 40% higher than Vrms -- so it definitely can't be equal currents, else you'd be getting extra power from somewhere!) Which is to say, a power factor around 0.5.
Your PF might be closer to, Idunno, 0.3 or something? Depends on RPM too, since you're clipping a ton of extra peak voltage at high RPM, or barely cutting through the peaks at low RPM. So the conduction angle varies, and how much of the supplied voltage you're wasting, varies.
But yeah, your ripple calculation is correct, just needs the right inputs. Exactly what the currents are, you'll have to figure out in testing, but if it's able to maintain output at all, it'll be somewhere around that time constant, and...some duty cycle (what duty, doesn't really matter!).
Like I said, you could get away with much less capacitance. But, I think, not a whole lot less than I recommended; 1000uF for example, you'd be hard pressed to find enough ripple current ratings, especially if this thing is going to be block mounted... erm, well, nevermind that heh, it's probably air cooled right, searing hot? Yeah, just find somewhere nice to stuff it, preferably away from heat... But anyway, a couple of those in parallel, or most 2200 or 4700uF units, I'd think, will handle that ripple current fine. With 14mF in there you should have no problem at all. Can also set the threshold a bit narrower, perhaps, raise the frequency, reduce ripple further.
Tim