I was looking at the first post, trying to identify the main idea. Nice trick, by the way!

My first thought was, why a second opamp would do a better job than just a simple piece of wire?

Then, without resorting to math and control theory, I've considered only the DC regime. It can be observed that the output voltage of a normal opamp follower will always be smaller than the input, because of the opamp's finite open loop gain. So, why adding even more voltage "loses" (with the second opamp) helps? Took me a while to see.
Because the voltage "loses" introduced by the second opamp are going into the
inverting input of the first opamp.
Therefore, the quantity lost by the second opamp will have the opposite effect, almost cancelling the voltage "lost" by the first opamp.

But hey, we can lose as much voltage as we want with just a resistive divider (instead of a second opamp). In theory, it should be possible to compensate for the exact voltage "loses" (but we'll need to know the open-loop gain of the opamp). In other words, we can configure the first opamp as a non-inverting amplifier, with its amplification only slightly bigger than unity, just enough bigger to compensate for the inherent voltage loses caused by its finite open-loop gain.
I mean, something like in the last schematic here:

The first two schematics are there only to compare the output voltage of each method. The opamp used is the same in all three schematics: an ideal opamp with programmable open-loop gain (Aol). The Aol in the printscreen was intentionally made very low (Aol=3), in order to exaggerate the errors caused by a finite Aol gain.
Notice how the last schematic outputs exactly 12V, so no error at all. The output is not affected by the Aol, because the R2/R1 divider was calculated assuming the open-loop gain is a known value.
Of course, in practice the Aol is not known, and also the Aol changes with frequency. But typical Aol is very high in practice, so knowing the exact Aol might not be critical when calculating the R2/R1 voltage divider. I don't know. It is not clear to me which type of feedback would be better in practice: with a second opamp, or with a resistive divider.
(there are a lot of variables to consider for a high ppm accuracy: bias/offset/frequency compensations, temp drift, noise, components aging, etc., and I didn't make any numerical estimates, no idea if in practice the resistive divider would be better or worst)