Author Topic: Feedback: Simple RF Analog Switch PCB with 50 Ohm Traces  (Read 192 times)

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Offline ChendyTopic starter

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Feedback: Simple RF Analog Switch PCB with 50 Ohm Traces
« on: November 27, 2024, 03:03:24 pm »
I'm trying to design a simple RF Antenna Switcher, I'm new to RF design.

I want a 50 Ohm controlled impedance trace between my Antenna connector (IPEX 20579-001E) and an RF Switch (BGS12P2L6)

I've been speaking to a PCB manufacturer, to determine the exact trace width to achieve 50 Ohms, given their PCB specifications.
I didn't want the trace width to be too thin, as manufacturing tolerances would impact the target 50-ohm impedance too much:
  - Bad: a 0.1mm trace with 0.01mm manufacturing tolerance (10% error)
  - Better: a 0.5mm trace with 0.01mm manufacturing tolerance (2% error)
         
So my question...
The PCB manufacturer mentioned:
"Because the impedance line is short and in the pad, it will cause dielectric losses."

Is my approach for the highlighted microstrip trace (polygon) correct? Please see the images below
 - The connector pad is essentially the same width as the desired 50 Ohm trace
 - The RF Switch pad is much smaller, so I have tapered the polygon as it approaches
 - I've tried to place the connector and switch as close to as possible
 - I've read that it's beneficial to remove the trace solder mask, to reduce dielectric losses

I'm aware of coplanar waveguides, but I have read they have higher losses at my frequencies of interest, a 5G antenna, up to 6 Ghz.

Any help is appreciated! : )
 
« Last Edit: November 27, 2024, 03:05:59 pm by Chendy »
 


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