Hack a USB Charger?

[Torquin]

I encounter USB chargers for phones or other equipment that all have limitations on charging current, depending on which port you connect to.
Example: https://www.amazon.com/dp/B0BFHDZYQ9?ref=ppx_yo2ov_dt_b_fed_asin_title

I purchased a couple of these USB charger wall outlets and they both failed miserably at delivering the rated output on each port. This brings up the question, why do any of these chargers have limitations on their output? Now, I do realize that they need to protect themselves from overheating, or worse, but I do not understand why they don't have the potential output of whatever the hardware will support, and by that I mean the actual amperage that can go through the device without overheating to failure.
I am trying to understand what's going on here, with the designs so that these limitations are in place. It seems to me that the device should get all of the power it wants, and the device being charged/powered will only consume what it needs, like a regular power cord. Take, for instance, a computer PSU, it may be rated at 750W but the computer will only consume what it needs, so the 750W is the limitation of the wiring and components inside the PSU.
Are the limitations in a USB charger because of the the actual hardware inside? As I said, I know that there are limitations of the overall hardware, but limiting the output on the USB-A port to 2.4A, when the USB-C port supposedly is limited to 3.6A, is what I don't understand, referencing the example above. In the above example, using a Samsung S21 (discharged to about 21% battery level), I get a charge that is negative, discharging the phone when plugged into the USB-A port, and a maximum measured 6W when connected to the USB-C (PD) port. This is completely unacceptable charging performance.
I am still of the thinking that the output should only be limited by the size of the wires/components inside.

Or, is some of the limitation coming from the device being charged, as it will not negotiate high-output from the charger for some reason?

What I am getting to is that I wonder about hacking the charger to allow them to output more current, to their hardware limitations.
Please educate me on what's going on here.

Thanks,
Chris

[tunk]

Are the limitations in a USB charger because of the the actual hardware inside?

Most likely, yes.
There may be some limits in the switching/charge controller.
You may get better answers if you post some photos of the PCB.

[Haenk]

Most of the chargers (the cheap ones) have their outputs connected, so nothing to gain there. No negotiating either, its "abilities" is communicated by a resistor.
The expensive ones from known 3rd parties like UGREEN and the non-fake major branded ones to negotiate via wire.
However no one - ever - sells you a charger capable of "stated output power times x" (with x siginificantly higher than 1). If you need more power, purchase a better/larger charger.
All these chargers (minus the crappy cheap ones) have been designed to "deliver power x, have feature y and the lowest price possible", nothing to tweak there, it is already doing the best it could by design.

[tunk]

And given the (lack of) quality of the USB part,
I wouldn't trust the 120V sockets either.

[radiolistener]

There is a well-known hack to get higher current out of your charger.
It’s called buying one that actually supports it 

[Benta]

Aliexpress rules.
Champagna service on a beer budget.

[Torquin]

So, I tried another outlet by the same company, with a supposed 60W output, but again, it failed. I was able to get about 6W out of it, charging my phone. I also tried a Leviton outlet, from Home Depot for 50 bucks, with a supposed 30W output, and again, it would not output as advertised. All of the outlets went back. It wold be easier to plug in a fast charging block that does output as expected.

I am still curious about hacking one to output plenty of wattage for what I want to charge. On to learning more about these outlet designs.

Thanks,
Chris