Author Topic: Trance Style Proteus 8.13  (Read 1817 times)

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Offline HarolTopic starter

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  • Country: pe
Trance Style Proteus 8.13
« on: October 17, 2023, 04:08:24 pm »
Hola Foro

Cordiales saludos
Una inquietud

A cuanto equivale  cada una de ellas en milésimas de pulgada Trance Style que viene por defecto en Proteus 8.13
CUAL DE ELLAS SERIA IDEAL  PARA 10A

    Trance Style:
    DEFAULT
    POWER1
    POWER2
    RELIEF
    SIGNAL1
    SIGNAL2
    T4
    T6
    T7.5
    T8
    T10
    T12
    T15
    T20
    T25
    T30
    T40
    T50
    T60
    T70
    T80
    T90
    T100
    T200
    T300
    T400
    T500

Existe o no una calculadora para  calcular los PAD,   (PAD 10A)
Se agradece Foro
 

Offline woofy

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Re: Trance Style Proteus 8.13
« Reply #1 on: October 17, 2023, 04:46:56 pm »

How much does each one of them equal in thousandths of an inch Trance Style that comes by default in Proteus 8.13
WHICH OF THEM WOULD BE IDEAL FOR 10A


It depends on information you have not provided such as copper weight, which layer, acceptable temperature rise above ambient, etc.
Kicad has a very nice calculator that will do it or there are online calculators such as this one:
https://www.4pcb.com/trace-width-calculator.html

Offline DavidAlfa

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Re: Trance Style Proteus 8.13
« Reply #2 on: October 17, 2023, 05:53:53 pm »
A cuanto equivale  cada una de ellas en milésimas de pulgada?
What's the equivalent of each in in thousands of inches?

The trace style number is exactly that, T20 means 20th.
It heavily depends on the trace length, T100 for 50mm will be ok, but 500mm will need a much thicker trace, at least 500-600th.
For large currents the best is to use polygons, drawing a large rectangle and filling it with copper, using all the available space in the pcb.

El número de pista indica exactamente eso, T20 son 20 milésimas.
El ancho depende mucho de la longitud, puedes usar T100 para 50mm, pero necesitaras algo mucho más grande para por ejemplo 500mm, mínimo T500 o T600.
Lo mejor es utilizar polígonos, dibujar un rectángulo y llenarlo de cobre, utilizando todo el área posible de la placa.
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