The real power route is supposed to go through the lamp, problem is that its resistance comes along, so no very easy way out.
Now R22/R24 is 330/82, so around 10mA and a quarter of 5V to Q22 and Q23 bases.
R24 voltage is what it is, so that the lower part of T2 can switch those transistors, and R22 is just its feeder.
So changing R22, or R24 to a potentiometer is not going to do anything to the actual feeder voltage.
Maybe the easiest permanent way is to remove R21 and replace the lamp with adjustable mini regulator board from China and add a LED to its output side, if needed.
Since C25 is the only reservoir and then missing you may need a new one, how big depends how low input your regulator accepts and how steady output is needed.
For a curiosity you can also put the regulator before the lamp and make the whole thing adjustable.
Lift CR13 and CR14 and connect them to regulator's input as a source, for output you can then use those new freed holes.
Then adjust the output so that the other side of the lamp is 5V, after that you can compare how the output compares to that earlier 8V.
For a curiosity you can also just lift R21 and see what it does to +/-15V.
The problem with a lamp as a voltage divider is that its resistance is temperature dependant.
So lifting R21 will change the resistance over the lamp as high as it can be and so drop the 8V as much as it can.
You can also find a low value potentiometer and try that in place of the lamp, but few Watts may not be enough, so better use a heavier one.
Then you can also test how the machine reacts when 5V changes.
BTW,
I'm still wondering how unregulated is changing to not unregulated over a lamp.