OK let's see if I got this about right ... I have a new plot from the Yaesu HT set to VW C4FM mode. The analyzer set to a res. BW of 100 Hz, and it's 100 kHz wide so as to compare better to the example plot I got for Mask D for 12.5 kHz BW digital (now that I know what I'm looking for).
(d)Emission Mask D - 12.5 kHz channel bandwidth equipment. For transmitters designed to operate with a 12.5 kHz channel bandwidth, any emission must be attenuated below the power (P) of the highest emission contained within the authorized bandwidth as follows:
(1) On any frequency from the center of the authorized bandwidth f0 to 5.625 kHz removed from f0: Zero dB.
What I interpret this to mean is that, inside these limits of +/- 5.625 kHz, there is no
requirement for the emmision to have any attenuation. however as seen it does drop off a little bit but that is OK.
(2) On any frequency removed from the center of the authorized bandwidth by a displacement frequency (fd in kHz) of more than 5.625 kHz but no more than 12.5 kHz: At least 7.27(fd−2.88 kHz) dB.
Now it gets more complicated because I can't generate a mask for an overlay, so taking only one point - my marker 2 is 6.0 kHz from Fo which is greater than 5.625 kHz. According to the equation -
7.27(fd−2.88 kHz) dB
we have 7.27 * (6.0 - 2.88) = 22.68 dB
My marker says -22.45, so close enough.
(3) On any frequency removed from the center of the authorized bandwidth by a displacement frequency (fd in kHz) of more than 12.5 kHz: At least 50 10 log (P) dB or 70 dB, whichever is the lesser attenuation.
Well, the HT is set to a Po of 0.5 W, however it's going through a 40 dB attenuator before the analyzer, but is it simply:
50 + 10 log(0.5) = 47 dB
So between 70 dB and 47 dB, 47 dB is the lesser attenuation.
So that looks about right. Not sure why they say "the lesser attenuation" seems like more attenuation would be better.
Any mistakes in understanding?