I just found this: http://www.circuitdiagram.org/24v-5a-power-supply.html
It is an implementation similar to that suggested by rsjsouza, can someone explain the operation?
From what I understand, the transistor is used to adjust the voltage and is controlled by the IC. But beyond that I do not understand each other.
When the power supply is turned on, the UA7824 will operate as it is intended (a voltage regulator) if the current is low - at this point the transistor is turned off and its voltage between the collector and emitter terminals (V
ce) will be the same as the difference between the output of the rectifier and the output voltage of 24V.
As the current flows from the in to the out pins of the UA7824, the resistor connected between the transistor's base and emitter pins will have a voltage across its terminals (ohm's law).
As the current increases at about 0,65~0,7A, the voltage across the resistor's terminals will be 0,65~0,7V (1 ohm resistor), thus also increasing the voltage between the base and the emitter (V
be) pins of the transistor. At that V
be voltage, the transistor then starts to let current flow between the emitter and the collector terminals, which shares the current output with the UA7824. The way the transistor lets more current flow through these terminals is to reduce its collector emitter voltage or V
ce.
As the current increases, most of it is flowing through the transistor but the UA7824 still performs its intended function of regulating the voltage output. For example, if the transistor starts letting too much voltage go through its terminals (by reducing too much its V
ce), the UA7824 will sense the voltage increase in the output and reduce its own current flow, which reduces the current flowing through the resistor, thus decreasing the V
be voltage and consequently increasing the V
ce voltage.
One important detail to consider is the fact this topology will dissipate a lot of heat (or power), thus reducing the available power to the PA itself. For example, if the output of the rectifier is around 30V at 5A, the transistor will have the voltage difference (30-24V) across its terminals and about 4~4,5A will flow through it, which means it will convert 27W (6V * 4,5A) to heat that will be dissipated through its case. This is more than 20% of 120W that the transformer can deliver and is the only reason why folks are suggesting to use a switching power supply.
There's really not much point in using a linear regulator to supply a class D output stage.
Although I agree 100% with this due to efficiency, I have seen in the past severe intermodulation noise between the SMPS and the class D output, especially when both switchers are out of sync. Keep in mind that intermodulation noise can happen even when the switchers are operating at very high frequencies, but close enough to reach the audible range. That can be fixed by syncing both switchers, but it may not be trivial.