This AN was very informative. It states that the JFET is most linear as a VCR when operated close to Rds(on), and that distortion rises significantly when Rds exceeds 10 x Rds(on). It reiterates that Vds must be kept low to minimize distortion, and that applying 1/2 of (AC) Vds to the gate keeps distortion at minimum.
Well gosh, this must've been mentioned only about a dozen times in the thread!
And then the crux:
- There are JFETs that are purpose-made for VCR application!
The VCR4N seems most suitable for my requirements. I ordered one from mouser, along with a genuine 2N4338.
For reference:
http://www.farnell.com/datasheets/40047.pdfNote that they hardly give any data, and no curves besides the extremely up-close drain curves -- which look reasonably controllable, but of course they do within such a small region, and it's not clear where cutoff lands (despite the label on the plot).
If they aren't some weird special design, they should be nothing more than devices selected for high Vgs(off), I think.
I made a circuit to measure Rds(on) plus Rds at different Vgs and corresponding distortion when applying a 775mV 1.3kHz signal. To avoid the interdependency between the Vgs DC bias and the AC signal fed from drain, I introduced an opamp.
This provided some interesting learnings;
VCR4N and 2N4338 don't actually have a Vgs(off) or Vp, they reach a max Rds at a certain Vgs which then does not increase with lower Vgs (approx 7.5 x Rds(on)
Hmm, this is not possible, or something is funny about the interpretation?
The datasheet clearly says Vgs(off) at Vds = 10V, Id = 1uA or whatever. It has cutoff like any other JFET, and so Rds(on) will go towards infinity as Vgs falls -- and within a decreasing span of drain voltage for which the response is linear, or else increasing distortion at fixed drain voltage. The drain-gate divider cannot fix this, as inevitably Vgs < Vgs(off) must occur at some point, and as it crosses the threshold, Id goes to ~0 resulting in distortion. (Which should be, mostly a zero-crossing sort of thing, due to the effect of the divider? Effectively as signal voltage goes negative, drain and source swap positions, so Vgs has the same response as for positive signals -- hence the half divider: the strategy is to put the gate "in the middle" between D and S, making the distortion symmetrical I think. It's not that it's halving drain voltage, it's that it's averaging both drain and source voltages together. Ah, I never noticed that before and merely took the trick for granted, makes sense.)
Are you measuring current exactly as indicated in the schematic, or actually Vds in which case Rs makes a divider with R4+R3 and anything else hanging off the circuit (presumably the probe is over a meg though)? That could have that kind of effect.
Tim