Here's a question for your smart guys...
Background: I have one of those cheap Chinese inverter boards that take 9-12VDC and steps it up over a wide adjustment range up to almost 300VDC. I currently have it set to 190VDC as that is the most common set point used to calibrate the 200V range on most DMM's. And in fact on the 2465 DMM it is an absolute calibration constant requirement. The problem with that board is that it's unregulated and bounces all over. One minute it's 188V and another 192V. So I've been looking for some way to regulate it and I found this which looks promising....
https://www.mouser.com/datasheet/2/268/20005399A-909415.pdf
The trouble is, how do I calculate the values of R1 and R2? It doesn't seem to give enough information other than one example for 5VDC. But I want 190.0V. Maybe I'm missing something. I sure would like to know what resistance values to start with and then tweak it to exactly 190.0V. 
Empirical finger in the air approach with casio's excellent solver so you don't even have to do any algebabooble.
Key is hiding in the datasheet fig 3-2.
Vout = 1.2 * (1 + R2 / R1) + iAdj * R2
iAdj = 10uA
pick R1 around 2.2K (finger in the air estimate - could be totally wrong!), solve for R2 = 364.4k
Bingo. 360k in stock.
360k + 1% = 363.3, a good 1k less than the max.
360k - 1% = 356.4k. Span is about 10k or so potentially here.
Dig in junk box, find 10k multi turn trimmer.
Thus:
R1 = 2.2K
R2 = 360k in series with 10k multi turn pot.
desired output voltage is 200v, min load is 300uA so this is not good enough. Whack a 100k resistor on the output to stop it oscillating.
Edit: I solved for 200v there because I didn't read the question properly